Respuesta :

sqdancefan

Answer:

  -4x^5y^3 -3x^4y^3 +x^5y^2

Step-by-step explanation:

The distributive property applies.

  [tex](4x^2y+3xy-x^2)(-x^3y^2)\\\\=(4x^2y)(-x^3y^2)+(3xy)(-x^3y^2)+(-x^2)(-x^3y^2)\\\\=\boxed{-4x^5y^3-3x^4y^3+x^5y^2}[/tex]