dubughicks25281 dubughicks25281
  • 09-12-2021
  • Mathematics
contestada

how to solve the following system y=(1/2)x^2+2x-1 and 3x-y=1

Respuesta :

halesbeauty6 halesbeauty6
  • 09-12-2021

Answer:

(0,-1),(2,5)

Step-by-step explanation:

3x-y=1

0.5[tex]x^{2}[/tex]+2x-1=y

Substitute the equation of y into the other equation

3x-(0.5[tex]x^{2}[/tex]+2x-1)=1

3x-0.5[tex]x^{2}[/tex]-2x+1=1

collect like terms

-0.5[tex]x^{2}[/tex]+x=0

Solve for x

x(-0.5x+1)=0

0=-0.5x+1

-1=-0.5x

x=2 x=0

Back substitute into the other original equation and solve for y

3(2)-y=1

6-y=1

y=5

(2,5)

3(0)-y=1

-1(-y)=-1(1)

y=-1

(0,-1)

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