Answer: The answer is X∈[3,12).
Answer:
-8≤3x-17<19
-8+8 ≤ 3x - 17 + 8 < 19 + 8
0 ≤ 3x - 9 < 27
0 ≤ 3x - 9 + 9 < 27 + 9
0 ≤ 3x < 36
0 ≤ 3x / 3 < 36/3
0 ≤ x < 12
So x can be 0 or less than 12. A number between 0 and 12
