[tex]y=-x+3~~.....(i)\\\\y = 4x-2~~....(ii)\\\\\text{Substitute}~ y = -x+3~ \text{in equation (ii):}\\\\\\-x+3 = 4x-2\\\\\implies 4x +x = 3+2\\\\\implies 5x = 5\\\\\implies x = \dfrac 55 =1\\\\\\\text{Substitute x= 1 in equation (i):}\\\\y= -1 +3 = 2\\\\\text{Hence}~ (x,y)=(1,2)[/tex]
