gnoodles gnoodles
  • 08-12-2021
  • Mathematics
contestada

Make the d subject of the formula c = kd^2 + e

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Аноним Аноним
  • 08-12-2021

[tex]c = k {d}^{2} + e \\ = > c - e = k {d}^{2} \\ = > {d}^{2} = \frac{c - e}{k} \\ = > d = \sqrt{ \frac{c - e}{k} } [/tex]

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