kimberlygill kimberlygill

07-12-2021
Mathematics

contestada

2cosAcosB =

• cos(A + B) + cos(A - B)
• sin(A - B) + tan(A + B)

Respuesta :

Аноним Аноним

07-12-2021

Answer:

2cosAcosB = cos( A + B ) + cos( A - B )

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