Respuesta :

loneguy

[tex]\dfrac{ 2+ 2i}{5+4i}\\\\\\=\dfrac{(2+2i)(5-4i)}{(5+4i)(5-4i)}\\\\\\=\dfrac{10-8i + 10i -8i^2}{5^2 -(4i)^2}\\\\\\=\dfrac{10+2i +8}{25+16}~~~~;[i^2 =-1]\\\\\\=\dfrac{18+2i}{41}\\\\\\=\dfrac{18}{41} + \dfrac{2}{41}i[/tex]

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