ndkjfgj5707 ndkjfgj5707
  • 09-11-2021
  • Mathematics
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5^2x-4×5x^+1-125=0. Pls how do I solve it very quickly???.

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ryanmcgraw531
ryanmcgraw531 ryanmcgraw531
  • 09-11-2021

Answer:

x=25

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

(52)(x)−(4)(5)x1−125=0

25x+−20x+−125=0

(25x+−20x)+(−125)=0(Combine Like Terms)

5x+−125=0

5x−125=0

Step 2: Add 125 to both sides.

5x−125+125=0+125

5x=125

Step 3: Divide both sides by 5.

5x/5=125/5

x=25

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