sawyesimmo sawyesimmo
  • 08-11-2021
  • Mathematics
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What is an equation of the line that passes through the points (8, -8) and (1,6)?

Respuesta :

Mathkot
Mathkot Mathkot
  • 08-11-2021

Answer:

[tex]\boxed{y = -2x + 8}[/tex]

Step-by-step explanation:

Equation of a straight line: y = kx + b

Points: (8,-8) and (1,6)

Сompose the system of equations:

[tex]\displaystyle \left \{ {{-8= 8k + b} \atop {6= k + b}} \right[/tex] [tex]\displaystyle \left \{ {{b= -8 - 8k} \atop {b=6 - k}} \right \Longrightarrow -8 - 8k = 6 - k[/tex]

[tex]-8 - 8k = 6 - k[/tex]

[tex]-7k = 14|:(-7)[/tex]

[tex]k = -2[/tex]

[tex]b = 6 - k = 6 - (-2) =6 + 2 = 8[/tex]

[tex]y = -2x + 8[/tex]

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