Yeah Bro ! I'm here ,
.Given that ;-
slope ( m) = 3/2
y-intercept (c) = -3
Now ,
we know the equation of straight line in slope intercept form;
I.e
y = mx+c
Just substitute m and c 's value , we get
y= (3/2)x +( -3)
or,. y = 3x/2 - 3
[tex]y = \frac{3x}{2} - 3 \\ y = \frac{3x - 6}{2} \\ 2y = 3x - 6 \\ 3x - 2y = 6\\ [/tex]
,
Hence 3x-2y = .6
3x-2y-6 =0 is the required equation.
