Hi there!
We can use the derived equation to solve:
[tex]t = \sqrt{\frac{2h}{g}}}[/tex], where:
h = height
g = acceleration due to gravity
Plug in the given values. Remember to CONVERT km to m:
32 km = 32 km * 1000 m / 1 km = 32,000 m
t = √(2(32000)/3.4) ≈ 137.199 sec
Part 2:
Use the derived equation:
vf = √2gh
vf = √(32000)(3.4) = 329.848 m/s
