shaunahollland shaunahollland
  • 10-10-2021
  • Mathematics
contestada

Solve for h in terms of g and u


4u²(2u²) /g = -2u²h -gh²/2 +h

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 12-10-2021

9514 1404 393

Answer:

  h = (1 -2u² ± √(1 -4u²-12u⁴))/g

Step-by-step explanation:

This is a quadratic in h, so there are two solutions.

Written in standard form, the given equation is ...

  (-g/2)h² +(1-2u²)h -8u⁴/g = 0

The quadratic formula tells you the solution for h is ...

  h = (-(1 -2u²) ±√((1 -2u²) -4(-g/2)(-8u⁴/g)))/(2(-g/2))

  h = (2u² -1 ± √(4u⁴ -4u² +1 -16u⁴))/-g . . . . . simplify

  h = (1 -2u² ± √(1 -4u²-12u⁴))/g . . . . . . . . collect terms

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