williamgriffiths19 williamgriffiths19

07-10-2021
Mathematics

contestada

[tex]6^{4x-9} =(\frac{1}{36} )^{x-4}[/tex]

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kamilmatematik100504 kamilmatematik100504

07-10-2021

[tex]\displaystyle \large \boldsymbol {} 6^{4x-9} =\bigg(\frac{1}{36} \bigg)^{x-4} \\\\\\ 6^{4x-9}=(6^{-2})^{x-4 }\\\\\\ 6^{4x-9}=6^{-2x+8} \\\\\\ 4x-9=-2x+8 \\\\\\ 4x+2x=9+8 \\\\\\ \boxed{x=\frac{17}{6}=2\frac{5}{6} }[/tex]

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