Answer:
For the equation given:
[tex]x + 2y = 16 \\ 2y = - x + 16 \\ y = - \frac{1}{2} x + 8[/tex]
for perpendicular lines, the relationship between their slopes is given by:
[tex]m _{1} \times m _{2} = - 1[/tex]
m1 is slope for one line, and m2 is slope for another line.
[tex] - \frac{1}{2} \times m_{2} = - 1 \\ \\ m_{2} = - 1 \times - 2 \\ { \underline{ \: \: m_{2} = 2 \: \: }}[/tex]
Therefore, equation is;
[tex]{ \boxed{ \boxed{y = 2x - 2}}}[/tex]
