Respuesta :

et762572

Answer: Option A

Step-by-step explanation:

[tex]4\left(x+2\right)=4\left(x-3\right)[/tex]

[tex]4x+8=4x-12[/tex]

[tex]4x+8-8=4x-12-8[/tex]

[tex]4x=4x-20[/tex]

[tex]4x-4x=4x-20-4x[/tex]

[tex]0=-20[/tex]

[tex]\mathrm{The\:sides\:are\:not\:equal}[/tex] = No solution

OverpoweredNoob

Answer:

A

Step-by-step explanation:

4(x + 2) = 4(x - 3),

4x + 8 = 4x - 12,                     The 4x from both sides cancel each other out

8 ≠ -12