russellstephens russellstephens
  • 08-09-2021
  • Mathematics
contestada

Do the operation and express the answer in a + bi form. Use fractions in your answer.
1/(8 + i)

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sqdancefan
sqdancefan sqdancefan
  • 10-09-2021

9514 1404 393

Answer:

 8/65 -(1/65)i

Step-by-step explanation:

When there is a complex number in the denominator, the denominator can be made real by multiplying numerator and denominator by the conjugate of the denominator.

  [tex]\dfrac{1}{8+i}=\dfrac{8-i}{(8+i)(8-i)}=\dfrac{8-i}{8^2-i^2}=\boxed{\dfrac{8}{65}-\dfrac{1}{65}i}[/tex]

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