Respuesta :

1nitch

Answer:

[tex]y {}^{2} - 11y + 30 \\ y {}^{2} - 5y - 6y + 30 \\ (y {}^{2} - 5y) - (6y + 30) \\ y(y - 5) - 6(y - 5) \\ (y - 6)(y - 5)[/tex]

manissaha129

Answer:

[tex]→ {y}^{2} - 11y + 30 \\ = {y}^{2} - 5y - 6y + 30 \\ = y(y - 5) - 6(y - 5) \\ = \boxed{(y - 5)(y - 6)}✓[/tex]

  • (y - 5)(y - 6) is the right answer.