Seudónimo Seudónimo
  • 07-09-2021
  • Mathematics
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hi i rlly need help!!

hi i rlly need help class=

Respuesta :

ghaithgh
ghaithgh ghaithgh
  • 07-09-2021

Answer:

The choice four;

[tex]12 {x}^{2} {z}^{3} \sqrt{y} [/tex]

Step-by-step explanation:

[tex] \sqrt{144 {x}^{4} y {z}^{6} } \\ \\ \sqrt{ {12}^{2}( {x}^{2} )^{2}y( z^{3} ) ^{2} } \\ = 12 {x}^{2} \sqrt{y} {z}^{3} [/tex]

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