Step-by-step explanation:
[tex] {x}^{2} = 2x - 5 \\ {x}^{2} - 2x + 5 = 0 \\ here \: a = 1 \\ b = - 2 \\ c = 5 \\ solution \: for \: x = \frac{ - b + or - \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - - 2 + \: or - \sqrt{ {( - 2)}^{2} - 4 \times 1 \times 5 } }{2 \times 1} \\ \frac{2 + or \: - \sqrt{4 - 20} }{2} \\ = (2 + \: or \: - \sqrt{ - 16} ) \div 2 \\ \frac{2 + 4i}{2} or \frac{2 - 4i}{2} \\ 1 + 2i \: or \: 1 - 2i \\ thank \: you[/tex]
