TwizzleIsAStudent
TwizzleIsAStudent TwizzleIsAStudent
  • 10-08-2021
  • Mathematics
contestada

Given three consecutive odd integers whose sum is 369, find the smallest of the three integers.

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fortressinthesky
fortressinthesky fortressinthesky
  • 10-08-2021

Answer:

Step-by-step explanation:

369 = x + (x+2) + (x+4)

369 = 3x + 6

363 = 3x

121 = x

now that we know that x = 121, we can solve the equation by plugging in the variable

369 = x + (x+2) + (x+4)

369 = 121 + 123 + 125

369 = 369

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Omm2 Omm2
  • 07-01-2022

The smallest three integers are 121,123 and 125.

Let, the smallest odd integers be n

Then according to the given condition,

[tex]n+(n+2)+(n+4)=369\\3n+6=369\\3n=363\\n=121[/tex]

So, the numbers are,

[tex]n=121\\n+2=121+2=123\\n+4=121+4=125[/tex]

Learn More:https://brainly.com/question/2254193

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