muralikrishnadogipar
muralikrishnadogipar muralikrishnadogipar
  • 09-08-2021
  • Mathematics
contestada

Find the slope of the line tangent to the graph of x²+2xy² +3y=31 at the point (2, -3)​

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sqdancefan
sqdancefan sqdancefan
  • 09-08-2021

9514 1404 393

Answer:

  22/21

Step-by-step explanation:

Taking the derivative, we have ...

  2x·dx +2y²·dx +4xy·dy +3·dy = 0

  dx(2x +2y²) +dy(4xy+3) = 0

At the given point, this is ...

  dx(2·2 +2·(-3)²) +dy(4·2·(-3) +3) = 0

  22dx -21dy = 0

  dy/dx = 22/21

The slope of the tangent at the point of interest is 22/21.

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