jazb2cool jazb2cool

09-08-2021
Mathematics

contestada

Find the area of triangle ABC to the nearest tenth if AB = 11 ft, ∠BCA = 67 , and ∠CAB = 28 .

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SplitterDragon SplitterDragon

09-08-2021

Answer:

30.7

Step-by-step explanation:

Assuming the angled are degrees and not radian.

side BC= (11÷sin67)•sin28= 5.6

angle ABC= 180-67-28=85°

A= 11•5.6•sin85÷2≈30.68

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