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  • 09-08-2021
  • Mathematics
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(cos θ) ( sin 2θ) -2 sin θ +2 =0

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Аноним Аноним
  • 09-08-2021

Answer:

[tex](cos \:\theta )(sin\: 2\theta)-2\:sin\: \theta +2=0[/tex] [tex]\Longleftarrow[/tex] substitute

[tex]sin\: \theta \: cos^{2} -sin \theta +1=0[/tex] [tex]\Longleftarrow[/tex] Divide both sides by 2

[tex]sin\theta (cos^{2} \theta -1)+1=0[/tex] [tex]\Longleftarrow[/tex] Factor

[tex]sin \theta (sin^{2} \theta )+1=0[/tex] [tex]\Longleftarrow[/tex] substitute

[tex]sin^{3} \theta =-1[/tex] [tex]\Longleftarrow[/tex] Isolate

[tex]sin \theta =-1[/tex]

[tex]\theta =\frac{3\pi }{2} ,\frac{7\pi }{2}[/tex]

OAmalOHopeO

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