Respuesta :

side of cube=5

We know

[tex]\boxed{\sf Side=\dfrac{Diagonal}{\sqrt{2}}}[/tex]

[tex]\\ \sf \longmapsto Diagonal =sude\times \sqrt{2}[/tex]

[tex]\\ \sf \longmapsto Diagonal=5\sqrt{2}[/tex]

[tex]\\ \sf \longmapsto Diagonal=5\times 1.4[/tex]

[tex]\\ \sf \longmapsto Diagonal=7cm[/tex]

caylus

Answer:

Hello,

Step-by-step explanation:

[tex]Using\ the\ Pythagorian's\ theorem,\\\\EC^2=EA^2+AC^2\\\\=EA^2+AB^2+BC^2\\\\=3*5^2\\\\EC=5\sqrt{3} \approx{8,660...}[/tex]

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