Respuesta :

itzsplendidfellow

[tex]{\huge{\boxed{\sf{\pink{☛Answer࿐}}}}}[/tex]

  • From the first mechanism, it can be seen that the Aluminum is reduced at cathode and Florine is oxidized at anode.

  • The ratio of aluminium and fluorine is the ratio of their change in oxidation number, i.e. 2:3

༒HOPE SO IT HELPS YOU༒

༒MARK ME AS BRAINLIEST༒

Ver imagen itzsplendidfellow

Otras preguntas