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  • 09-07-2021
  • Mathematics
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Given P(B | A)=0.75, P(A ∩ B)=0.15, P(B’)=0.7, find P(A ∪ B)

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LammettHash
LammettHash LammettHash
  • 09-07-2021

By definition of conditional probability,

P(B | A) = P(A ∩ B) / P(A)

==>   P(A) = P(A ∩ B) / P(B | A) = 0.15/0.75 = 0.2

By definition of complement,

P(B') = 1 - P(B)

==>   P(B) = 1 - P(B') = 1 - 0.7 = 0.3

Now by the inclusion/exlcusion principle, we have

P(A U B) = P(A) + P(B) - P(A ∩ B)

==>   P(A U B) = 0.2 + 0.3 - 0.15 = 0.35

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