Respuesta :

Wallind123

Total outcomes=6 i.e{1,2,3,4,5,6 }

No.of favourable outcomes = 3 i.e {I, 3,5}

P(odd)=3/6=1/2

Answer:

1/ 2

Step-by-step explanation:

[tex]probability \: of \:an \:event\: = \frac{number \: of \: favorable outcomes}{total \: number \: of \: outcomes} [/tex]

favorable outcomes = odd numbers

=1, 3, 5

number of favorable outcomes = 3

total outcomes

= 1, 2, 3, 4, 5, 6

total number of outcomes = 6

probability = 3/ 6

= 1/ 2

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