Answer:
(b) [tex]x \ge -3[/tex]
Step-by-step explanation:
Given
[tex]g(x) = \sqrt{x + 3}[/tex]
Required
The domain
For [tex]g(x) = \sqrt{x + 3}[/tex] to be defined, the following must be true
[tex]\sqrt{x + 3} \ge 0[/tex]
Square both sides
[tex]x + 3 \ge 0[/tex]
Subtract 3 from both sides
[tex]x \ge -3[/tex]
Hence, the domain is:
(b) [tex]x \ge -3[/tex]
