Brandidanii Brandidanii
  • 10-06-2021
  • Mathematics
contestada

[tex]\frac{(csc x+1)(csc x-1)}{csc^2x}\\[/tex]

cscθ·cos^2θ+sinθ= cscθ

Respuesta :

Trancescient
Trancescient Trancescient
  • 10-06-2021

Step-by-step explanation:

[tex]\frac{( \csc x+1)( \csc x-1)}{ \csc ^2x} = \frac{ { \csc }^{2} x - 1}{ \csc^{2} x} \\ = 1 - \sin^{2} x = \cos^{2} x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

b. Since csc theta = 1/sin theta, we can multiply both sides by sin theta and you will end up with

[tex] \cos^{2} \theta + \sin^{2} \theta = 1[/tex]

which is an identity.

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