Respuesta :

maacastrobr

Answer:

8.324 g

Explanation:

First we convert 750.0 mL into L:

  • 750.0 mL / 1000 = 0.750 L

Then we calculate the required number of moles of CaCl₂, using the definition of molarity:

  • Molarity = moles / liters
  • Molarity * liters = moles
  • 0.100 M * 0.750 L = 0.075 mol

Finally we convert 0.075 moles of CaCl₂ into grams, using its molar mass:

  • 0.075 mol * 110.98 g/mol = 8.324 g

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