Answer: 7.36 moles of [tex]CaBr_2[/tex] will be produced.
Explanation:
We are given:
Moles of NaBr = 14.72 moles
The given chemical equation follows:
[tex]2NaBr+Ca(OH)_2\rightarrow CaBr_2+2NaOH[/tex]
By the stoichiometry of the reaction:
2 moles of NaBr produces 1 mole of calcium bromide
So, 14.72 moles of NaBr will produce = [tex]\frac{1}{2}\times 14.72=7.36mol[/tex] of calcium bromide
Hence, 7.36 moles of [tex]CaBr_2[/tex] will be produced.
