youyeonju0622 youyeonju0622
  • 09-06-2021
  • Mathematics
contestada

In a triangle HIJ, i = 6.6 inches, j = 6.4 inches and Angle,H=62º. Find the length of h, to the
nearest 10th of an inch.

In a triangle HIJ i 66 inches j 64 inches and AngleH62º Find the length of h to the nearest 10th of an inch class=

Respuesta :

adefunkeadewole adefunkeadewole
  • 14-06-2021

Answer:

7.6 inches

Step-by-step explanation:

We solve the above question using the Law of Cosines.

The formula is given as:

h² = i² + j² - 2ij Cos H

h = √i² + j² - 2ij Cos H

From the above question:

i = 6.6 inches

j = 6.4 inches

Length h = ?

Angle H=62º.

Hence:

h= √6.6² + 6.4² - 2 × 6.6 × 64 × Cos 62

h = √43.56 + 40.96 - 84.48 × Cos 62

h = 7.64292 inches

Approximately to the nearest tenth, Length h = 7.6 inches

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