Given that cot A = 16/63 and that angle A is in Quadrant I, find the exact value of cscA in simplest radical form using a rational denominator.

Given that cot A 1663 and that angle A is in Quadrant I find the exact value of cscA in simplest radical form using a rational denominator class=

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Answer:

Below in bold.

Step-by-step explanation:

cot = adjacent side / opposite side = 16/63

So the  hypotenuse = √(16^2 + 63^2)

= √4225

= 65.

So csc A = hypotenuse /opposite side

= 65/63