Answer:
The answer is "4.8 and 463.011"
Step-by-step explanation:
Please find the complete question in the attached file.
Given:
side[tex]= 9.6 \ in\\\\[/tex]
let the radius of the ball
[tex]2r=9.6 \ in\\\\r=\frac{9.6}{2}\\\\r= 4.8 \ in\\\\[/tex]
The radius of the basketball [tex]= 4.8 \ in\\\\[/tex]
The volume of the basketball[tex]=\frac{4}{3}\pi r^3=\frac{4}{3}\times 3.14 \times 4.8^3= 463.011 \ in^3[/tex]
