Answer:
27 g
Explanation:
From the question,
n = Mv...................... Equation 1
Where n = number of mole of Al₂SO₄, M = Molarity of Al₂SO₄, v = Volume of the solution.
Given: M = 0.12 mol/L, v = 1.5 L.
Substitute these values into equation 1
n = 0.12×1.5
n = 0.18 mol
Also,
n = Mass(m)/Molar mass (m')
n = m/m'.
m = n×m'......................... Equation 2
Given: The molar mass of Al₂SO₄ = (27×2)+32+(16×4) = 150 g/mol
Substitute into equation 2
m = 0.18×150
m = 27 g
