Answer:
66 sq.yd
Step-by-step explanation:
Given,
Base of the parallelogram = 11 yd
Height of the parallelogram = 6 yd
Therefore,
Area of the parallelogram = base × height
= 11 yd × 6 yd
[tex] = 66 {yd}^{2} [/tex]
Hence,
Area of the parallelogram is 66 sq. yd
