Answer:
It is proved that sin20=2sin0.cos0
Explanation:
Given
[tex]0=30[/tex] °
[tex]sin20=2sin0.cos0[/tex]
Substituting the value of "0" on both the sides, we get -
[tex]sin2 (30) =2sin 30 * cos 30\\sin 60 = 2 * sin 30 * cos 30 \\0.866 = 2 * 0.5 * 0.866\\0.866 = 0.866[/tex]
Since LHS = RHS
we can say that [tex]sin20=2sin0.cos0[/tex]
