Answer:
This explanation from Physics/Geometry
60o |
|
| Fy (the vert. comp.)
↑
← 30o |
Fx (the horizontal componenet)
F = √(Fx2 + Fy2)
Fy = 50 · cos 60o = 50 · (1/2) = 25 N
Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N
I see, that vector sign did not appear in my comment above, so the vector equation is
→ → →
F = 50 cos 30o i + 50 cos 60o j
Explanation:
