hannahmckinley4
hannahmckinley4 hannahmckinley4
  • 09-03-2021
  • Mathematics
contestada

10 in.
9 in.
11 in.
help please!!!

10 in 9 in 11 in help please class=

Respuesta :

vanesha376
vanesha376 vanesha376
  • 09-03-2021

[tex] \pink{\boxed{\rm Answer + Explain}} [/tex]

.

Area of parallelogram

[tex] \rm L = base \times hight [/tex]

[tex] \rm L = 11 \times 9 [/tex]

[tex] \blue{\boxed{\rm L = 99 {in}^{2}}} [/tex]

.

around of parallelogram

[tex] \rm = (2 \times base) + (2 \times side) [/tex]

[tex] \rm = (2 \times 11) + (2 \times 10) [/tex]

[tex] \rm = 22 + 20 [/tex]

[tex] \blue{\boxed{ \rm = 42 in }} [/tex]

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