Respuesta :

Simple...

you have: [tex]F= \sqrt[a]{ \frac{ 16a^{2} + 8a^{2} }{ 4a^{2}+ 2a^{2} } } [/tex]

As far as I can see this is pretty simple....

Simply divide it-->>>>

the [tex] a^{2} [/tex] cancel out-->>

[tex]F= \sqrt[a]{ \frac{24}{6} } [/tex]

[tex]F= \sqrt[a]{4} [/tex]

Thus, your answer.

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