Answer:
[tex] \angle R < \angle S < \angle Q[/tex]
Step-by-step explanation:
In ΔQRS, RS = 16, SQ = 9, and QR = 15.
From above info it is obvious that:
SQ < QR < RS
In a triangle, angle opposite to smallest side is smallest and angle opposite to largest side is largest.
Therefore,
[tex] \angle R < \angle S < \angle Q[/tex]
