Answer:
Step-by-step explanation:
Sine doesn't have an inverse, until you restrict the domain to -pi/2 to pi/2. If you don't restrict the domain, then the inverse doesn't exist. Im going to assume the domain is restricted.
Switch the x and y values
[tex]x= \pi/4+ \sin(y)[/tex]
Subtract pi/4 on both sides
[tex]x- \pi/4= \sin(y)[/tex]
Take the arcsine of both sides
[tex]\arcsin(x- \pi/4)=y[/tex]
