The number of men will be 42 if there are 5 hens, 10 goats, and 8 cows.
It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.
We have:
In one house, there are 5 hens, 10 goats, and 8 cows.
Let H be man's head
H < 65
Total heads = 5 + 10 + 8 =23
Man's heds = 65 - 23 = 42
Thus, the number of men will be 42 if there are 5 hens, 10 goats, and 8 cows.
Learn more about the inequality here:
brainly.com/question/19491153
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