Answer:
the original volume is 4.0L
Step-by-step explanation:
Step one:
given data
V1= ?
T1= 52 °C
V2= 6.1L
T2= 79° C
Step two
applying the volume temperature relationship, which is
V1/T1= V2/T2
substituting we have
V1/52= 6.1/79
cross multiply we have
52*6.1= V1*79
317.2= 79V1
divide both sides by 79
V1= 317.2/79
V1=4.0L
