Answer:Total Inductive reactance XL =538.63 Ω
Explanation:
Parallel combination for Effective inductance is calculated as
L total = [tex]\frac{1}{1/L1 + 1/L2 + ... 1/Ln}[/tex]
=[tex]\frac{1}{1/5 + 1/2}[/tex]
[tex]\frac{1}{0.2 + 0.5 \\}[/tex]
=[tex]\frac{1}{0.7}[/tex]
=1.42857H
Inductive reactance XL = 2 πFL
where f= frequency= 60Hz
L= Effective inductance=1.42857H
Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857
=538.63Ω
