Answer:
[tex] \frac{1}{8xy \sqrt{y} } [/tex]
Step-by-step explanation:
[tex](64 {x}^{2} {y}^{3} )^{ - \frac{ 1 }{2} } \\ \\ = \frac{1}{(64 {x}^{2} {y}^{3} )^{\frac{ 1 }{2} } } \\ \\ = \frac{1}{ \sqrt{64 {x}^{2} {y}^{3}} } \\ \\ = \frac{1}{ \sqrt{ {(8xy)}^{2} y} } \\ \\ = \frac{1}{8xy \sqrt{y} } [/tex]
