The final temperature of the system : 31.5 °C
Further explanation
Given
55.5 g Al, 95 C
500 g water, 30 C
C Al = 0.900 J/gºC
Required
the final temperature
Solution
Q in = Q out
Q absorbed = Q released
Q water = Q Aluminium
[tex]\tt 500\times 4.186\times (t-30)=55.5\times 0.9\times (95-t)\\\\2093t-62790=4702.5-49.5t\\\\2142.5t=67492.5\rightarrow t=31.5^oC[/tex]
