Answer: yes it is t={1}
PREMISES
16–2t=5t+9
CALCULATIONS
16–2t=5t+9
(16–9)-(2t-2t)=5t+2t+(9–9)
7–0=7t+0
7t=7
7t/7=7/7
t=1/1
t=
1
PROOF
If t=1, then the equations
16–2t=5t+9
16–2(1)=5(1)+9
16–2=5+9 and
14=14 prove the root (zero) t=1 of the statement 16–2t=5t+9
Step-by-step explanation:
