Answer:
30.405°C
Explanation:
Using the formula for heart capacity;
Q = mcΔt
m is the mass = 150g = 0.15kg
initial temperature = 22°C
Quantity of heat = 3240J = 3.24kJ
specific heat capacity of ethanol = 2.57 [kJ/kg K]
Substitute and get the final temperature
3.240 = 0.15(2.57)(T - 22)
3.240 = 0.3855(T-22)
3.240/0.3855 = T - 22
8.405 = T - 22
T = 22+8.405
T = 30.405°C
Hence the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol is 30.405°C
