Step-by-step explanation:
radius=10cm
<A0B=90°
Length of arc AB,
[tex] 10 \times \frac{\pi}{2 } = 5 \times 3.14 = 15.4cm[/tex]
[tex]perimeter \: of \: quadrant = \: 10 + 10 + 15.4 = 35.4cm[/tex]
Area of quadrant=
[tex] \frac{90}{360 } \times 3.14 \times {10 }^{2} = 78.5cm ^{2} [/tex]
